Stars  Active and Dead incl. BlackHoles {© 03/12/17}
Note: apart from the theories proposed by Isaac Newton and Henri Poincaré, all the formulas and proposals provided below are exclusively from CalQlata.
Mathematical proof for the following theories is provided in:
PHILOSOPHIÆ NATURALIS PRINCIPIA MATHEMATICA (Revision IV).
All celestial bodies; stars, galactic forcecentres, planets, moons, comets, etc. originally comprised the same matter and were ejected from the ultimatebody during the 'Big Bang'.
An Active Star
After a star has collected sufficient satellite mass (planets) to create the internal frictional heat through spin energy necessary to generate atomic fission it will have become active (see Stars & The Gas Planets). In this way, active stars create the universe's energybank together with the lighter elements and ultimately, hydrogen (protonelectron pairs).
All the heavy elements are created in the ultimatebody; the only place with sufficient gravitational (magnetic charge) energy to generate the fusion required to create them.
During its life, an active star continually emits (radiates) the energy generated by its nuclear fission in the form of alpha and beta particles, and electromagnetic radiation.
Apart from a little core heat, the only energy a star will possess at the end of its life will be gravitational, but it will have retained all the mass it had when originally ejected from the ultimatebody.
A star's mass, and therefore its gravitational energy, does not [significantly] alter throughout its life. However, as it grows older, having converted most of its matter to hydrogen, gravitational attraction at a star's surface decreases as it grows in size.
i.e. the greater a star's density, the greater its gravitational attraction at its surface
and the greater a star's mass, the greater its gravitational energy
A Dead Star
A dead star is one that has converted all its matter to lighter elements and hydrogen atoms, and therefore generates insufficient internal frictional heat for fission to occur.
Black Holes
A blackhole is simply a star with no satllelites of its own, or no forcecentre, and therefore generates no internal heat through planetary spin. I.e. it cannot emit electromagnetic radiation; making it impossible to observe visually/directly.
As a theoretical exercise (that has no place in reality) it is possible to predict today's misconception of a blackhole as follows:
It is currently believed that a blackhole is body with sufficient density to prevent photons from escaping its surface.
For example; VY Canis Majoris has a radius (9.879082E+11 m) almost 20 times larger than that of the minimum iron star that could be expected to collapse to an instant blackhole (5.3218365E+10 m) according to the Calculations below⁽¹⁾
Formulas
Whilst CalQlata has adopted 'U' to symbolise energy, with due respect to Henri Poincaré we have adopted his symbol 'E' for this page
From Isaac Newton's gravitational force: F = G.m₁.m₂ / R² → m.g = G.m₁.m₂ / R² → g = G.m / R²
The following Table contains the principle formulas used in the Calculations (below) to determine the properties of collapsed and active stars and blackholes.
Formula  Variables & Constants  Comments 
V = 4/3 π.R³  V = volume of a sphere R = radius of a sphere 

ρ = m/V  V = volume of a sphere ρ = density m = mass 

R = ³√[3.m / 4π.ρ]  R = radius of a sphere ρ = density m = mass 
Calculating a star's radius based upon its known density and mass 
F = G.m₁.m₂ / R²  F = centripetal force between a force centre and an orbiting body G = Newton's gravitational constant m₁ = mass of the force centre m₂ = mass of the orbiting body R = the straightline distance between the centres of the force centre and the orbiting body 
The attracting (gravitational) force between a force centre (a sun) and an orbiting body (a planet) 
F = m.a = m.g  F = force m = mass a = acceleration g = gravitational acceleration 
As described by Isaac Newton 
g = G.m / R²  g = gravitational acceleration at 'R' G = Newton's gravitational constant m = mass of force centre (star) R = radius of the force centre (star) 
Used to determine the gravitational acceleration of a mass at radial distance 'R' from its centre 
p = ρ.R  p = core masspressure of the hydrogen gas ρ = average planet density R = planet radius 
Masspressure at planet core 
p = g/G  p = masspressure g = gravitational acceleration G = Newton's gravitational constant 
special case: unknown 
m = p.R²  m = mass of body p = masspressure at interface of iron core and hydrogen gas R = radius of star 
Used to determine the mass of a star of known radius from its core pressure⁽³⁾ 
p₁/R₁ = p₂/R₂  R₁ = radius of star₁ R₂ = radius of star₂ p₁ = masspressure at core of R₁ p₂ = masspressure at core of R₂ 
A relationship between any two masses of the same average density⁽³⁾ 
R₁/R₂ = g₁/g₂  R₁ = radius of star₁ R₂ = radius of star₂ g₁ = gravitational acceleration₁ g₂ = gravitational acceleration₂ 
A relationship between any two masses of the same average density⁽³⁾ 
R₁/ρ₁ = R₂/ρ₂  R₁ = radius of star₁ R₂ = radius of star₂ ρ₁ = density of star₁ ρ₂ = density of star₂ 
A relationship between any two masses of the same material (e.g. hydrogen)⁽³⁾ 
R₂ = (3.m₂.R₁ / 4.π.ρ₁)⁰˙²⁵  R₁ = radius of star₁ R₂ = radius of star₂ ρ₁ = density of star₁ m₂ = mass of star₂ 
Used to find the radius of a star of known mass of the same material (e.g. hydrogen)⁽³⁾ 
E = m.c²  E = relativistic momentum (energy) in 'm' at 'c' m = mass of star c = speed of light in a vacuum 
Limiting momentum (energy) in a body of mass (m) when moving at the speed of light (c) 
E = m.g.R  E = gravitational energy in 'm' m = mass of body R = radius of 'm' g = gravitational acceleration at 'R' 
Gravitational energy in a body of mass (m) at radius 'R' 
E = G.m²/R  G = Newton's gravitational constant E = gravitational energy of star m = mass of star R = radius of star 
Gravitational energy 
v² = 2.a.R  c = speed of light g = gravitational acceleration at 'R' R = radius of body (star) 
Relationship between velocity and acceleration 
c² = 2.g.R  c = speed of light g = gravitational acceleration at 'R' R = radius of body (star) 
Used to determine the equivalent limiting radius 'R' below which light cannot escape a given mass 
v² = 2.G.m/R  G = Newton's gravitational constant m = mass of star R = radius of star v = velocity 
Newton's escape velocity for a planetary body 
m = ¾(E/G)⁰˙⁶ / ρ⁰˙²  m = mass of body (star) E = gravitational energy G = Newton's gravitational constant ρ = density of body 
Alternative formula for the mass of a body 
m = (3.c⁶ / 32.π.ρ.G³)⁰˙⁵ 
m = mass of body (star) c = speed of light G = Newton's gravitational constant ρ = density of body 
Minimum (limiting) mass of a star that can be expected to collapse directly to form a black hole 
Calculations {© 15/02/17}
The following comprises a series of calculations that predict the expected ultimate destiny of three stars according to the above formulas and data developed in CalQlata's 'Laws of Motion' web page.
The Earth's Sun
Known Properties (active):
mass (m) = 1.98850E+30 kg
radius (R) = 6.95710E+08 m
Calculated Properties (active):
Volume (V) = 4/3 . π.R³ = 1.4105E+27 m³
average density (ρ) = m/V = 1409.7829 kg/m³
gravitational acceleration (g) = G.m/R² = 274.1755834 m/s²
gravitational energy (E) = m.g.R = 3.793E+41 J
Known Properties (dead) assuming the density of iron:
average density (ρ) = 7870 kg/m³ ⁽⁴⁾
mass (m) ≈1.98850E+30 kg
Calculated Properties (dead):
volume (V) ≈ 4/3 . π.R³ ≈ 2.52668E+26 m³
radius (R) ≈ ³√[3.m / 4π.ρ] ≈ 3.921818E+08 m
gravitational acceleration (g) ≈ G.m/R² ≈ 862.8 m/s²
2.g.R ⁽⁵⁾ ≈ 6.767493E+11 m²/s² (c² = 8.987552E+16)
Given that 2.g.R is so much less than c², it is unlikely that the earth’s sun will become a blackhole immediately after collapse
VY Canis Majoris
Known Properties (active):
Radius (R) = 9.87908E+11 m
mass (m) = 5.967E+31 kg
Calculated Properties (active):
volume (V) = 4/3 . π.R³ = 4.03867E+36 m³
average density (ρ) = m/V = 1.477467E05 kg/m³
gravitational acceleration (g) = G.m/R² = 4.0802E03 m/s²
gravitational energy (E) = m.g.R = 2.4052224E+41 J
Known Properties (dead): (assuming the density of iron)
mass (m) = 5.967E+31 kg
average density (ρ) = 7870 kg/m³ ⁽⁴⁾
Calculated Properties (dead):
volume (V) ≈ 4/3 . π.R³ ≈ 7.58196E+27 m³
radius (R) ≈ ³√[3.m / 4π.ρ] ≈ 1.21870E+09 m
gravitational acceleration (g) ≈ G.m/R² ≈ 2681.156 m/s²
2.g.R ⁽⁵⁾ ≈ 6.53505E+12 m²/s² (c² = 8.9875518E+16)
Whilst VY Canis Majoris is very large, it has a mass little larger than our sun and therefore is unlikely to collapse into an instant black hole
Minimum Potential BlackHole Star
Known Properties (dead):
c² = 2.g.R = 8.9875518E+16 m²/s²
average density (ρ) = 7870 kg/m³ (assuming the density of iron)
Calculated Properties (dead):
mass (m) = √(3.c⁶ / 32π.ρ.G³) = 9.6237854E+37 kg
volume (V) = m/ρ = 1.22284441E+34 m³
radius (R) = ³√(3.V / 4π) = 1.42920392E+11 m ⁽⁵⁾
gravitational acceleration (g) = G.m/R² = 314425.10331 m/s²
Known Properties (active):
mass (m) = 9.62378552E+37 kg
Calculated Properties (active):
radius (R) = ⁴√(R₁⁴ . m₁/m₂) = 5.802742927E+10 m
volume (V) = 4/3π.R³ = 8.1844330782E+32 m³
average density (ρ) = m/V = 117586.46475 kg/m³ ⁽⁴⁾
gravitational acceleration (g) = G.m/R² = 1907387.5622 m/s²
gravitational energy (E) = m.g.R = 1.0651682497E+55 J
2.g.R = 8.9875517874E+16 m²/s² (c² = 8.9875517874E+16)
A blackhole at the time of collapse (see Neutron Star below)
The above results are summarised in the following Table (input data):
Units  The Earth’s Sun  VY Canis Majoris  Minimum Potential BlackHole Star  
Active  
mass  kg  1.98850E+30  5.967E+31  9.6237855E+37 
radius  m  6.95710E+08  9.879082E+11  5.802743E+10 
volume  m³  1.41050E+27  4.03867E+36  8.1844331E+32 
average density  kg/m³  1409.78293  1.477467E05  117586.46475 
gravitational acceleration  m/s²  274.175583  4.08021E03  1907387.5622 
gravitational energy  J  3.79299803E+41  2.405222E+41  1.06516825E+55 
Dead  
mass  kg  1.98850E+30  5.967E+31  9.6237855E+37 
radius  m  392181784  1.218702E+09  1.429204E+11 
volume  m³  2.52668E+26  7.58196E+27  1.2228444E+34 
average density ⁽⁴⁾  kg/m³  7870  7870  7870 
gravitational acceleration  m/s²  862.800588  2681.14672  314425.10331 
2.g.R ⁽⁵⁾  m²/s²  6.76749348E+11  6.5350384E+12  8.9875518E+16 
c²  m²/s²  8.9875518E+16  8.9875518E+16  8.9875518E+16 
Properties of a BlackHole {© 15/02/17}
From our formulas above:
v² = 2.a.R
Special [limiting] case to trap photons: c² = 2.g.R → g = c² / 2.R
Gravitational (potential) energy: E = m.g.R → E = m.R.c² / 2.R
Limiting gravitational energy that will trap photons: E = m.c² / 2
i.e.: Kinetic energy of the mass at light speed: E = ½.m.c²
If we apply these calculations to the above (iron) limiting blackhole:
E = m.g.R = 9.6287855E+37 x 314425.10331 x 1.4292039174E+11 = 4.32696038E+54 J
KE = ½.m.c² = 9.6287855E+37 x 2997924582² ÷ 2 = 4.32696038E+54 J
CalQlata has therefore shown that the gravitational energy in a planet that will trap photons is equal to its kinetic energy at light speed
Assuming that the limiting mass for a star that can be expected to collapse to form an instant black hole (trap highenergy photons) is governed by the relationship 2.g.R = c², its mass can be calculated thus:
m = √(3.c⁶ / 32.π.ρ.G³) = 9.62378551609E+37
and its radius; R = 5.3218365E+10 m⁽¹⁾
However, it is claimed that all black holes are neutron stars, i.e. they collapse to the density of a neutron. If this is so its properties may be calculated as follows:
Neutron Star
The properties of a neutron:
m = 1.6749272928E27 kg
R = 1.11328405737E15 m
V = 5.77971706488E45 m³
ρ = 2.8979399407E+17 kg/m³ ⁽⁶⁾
The radius of this star is related to its mass thus:
R³ = 3.m / 4.π.ρ
R = ³√(3.m / [4 x π x 2.8979399407E+17])
R = ³√m . ³√(3 / [4 x π x 2.8979399407E+17])
R = 9.37433933214E07 x ³√m
According to Newton: v² = 2.G.m/R
Limiting condition: c² = 2.G.m/R
R = 2.G.m / c²
2.G.m / c² = 9.37433933214E07 x ³√m
m/³√m = ¹˙⁵√m = 9.37433933214E07 x c²/2.G
m = (9.37433933214E07 x c² ÷ 2.G)¹˙⁵ = 1.58677073182E+31 kg
{check: m = √(3.c⁶ / 32.π.ρ.G³) = 1.58677073182E+31 kg}
which represents the minimum mass that could create a neutron star on collapse
Its radius: R = 2.G.m / c² = 23556.57050854 m
The gravitational acceleration at its surface is:
g = c² / 2.R = 1.90765285297E+12 m/s²
{check: g = G.m/R² = 1.90765285297E+12}
KE = ½.m.c² = 7.13059206345E+47 J
Eg = m.g.R = 7.13059206345E+47 J
confirming CalQlata's claim that the gravitational energy of a blackhole is equal to its kinetic energy at light speed
The problem is, however, whether or not iron can collapse to the density of a neutron with the above mass(es), because in order to do so, there can be no protons or electrons (or photons) within the body.
Moreover, its ultimate density is governed by the compressibility or iron.
Constants {© 02/02/17}
For all stars (and planets): 2.π.R.G.ρ / g = 1.5 {radians}
Proof: 2.π.R.G.ρ / 1.5 g = 1
4/3.π.R.G.(m/(4/3.π.R²)) / g
G.m / g.R² = 1
g = G.m / R²
We can check the above calculations as follows:
The Earth’s Sun
active: 2.π.G.ρ.R / g = 2.π.G x 1409.782932 x 6.95710E+08 ÷ 274.0806631 = 1.5 {radians}
dead: 2.π.G.ρ.R / g = 2.π.G x 7870 x 3.921817841E+08 ÷ 862.5018838 = 1.5 {radians}
VY Canis Majoris
active: 2.π.G.ρ.R / g = 2.π.G x 1.477467E05 x 9.87908E+11 ÷ 4.07880E03 = 1.5 {radians}
dead: 2.π.G.ρ.R / g = 2.π.G x 7870 x 1.21870E+09 ÷ 2680 = 1.5 {radians}
Minimum Potential BlackHole Star
active: 2.π.G.ρ.R / g = 2.π.G x 117601 x 5.80350E+10 ÷ 1907222 = 1.5 {radians}
dead: 2.π.G.ρ.R / g = 2.π.G x 7870 x 1.42945138E+11 ÷ 314370.67118 = 1.5 {radians}
This constant also applies to planets (e.g. the earth):
2.π.G.ρ.R / g = 2.π.G x 5508.25830105342 x 6371000.685 ÷ 9.80663139027614 = 1.5 {radians}
A useful constant (K), based upon Newton's theories, for all matter is:
K = g / ρ.R = 2.7954278140935E10 m³/s²/kg
and
G = K / 4/3π = 6.6735923200433E11 m³/s²/kg
EHT: Black Hole
Looking at this recently released photograph, we (at CalQlata) are left with a number of concerns:
1) There is no such thing as a singularity. A black hole is simply a large body of matter too cold to emit electromagnetic energy strong enough for us to detect.
2) And even if there were, by definition you would not be able to see it. Therefore, this cannot be a photograph of a blackhole. It is simply a photograph of a black space.
3) Singularities do not exist because they defy the laws of thermodynamics
4) Even if the dark area in the centre of the photograph is a singularity, why is it so large? The Schwarzschild’s radius for a singularity would be much smaller than depicted in this photograph
5) Einstein's theories of relativity have already been proven incorrect; so there is no such thing as an 'eventhorizon'
6) The photograph was taken using radiotelescopes, which cannot detect colour, so how do we know that the coloured regions of the photographs are orange
7) The image looks exactly like a large star orbiting a large galactic forcecentre; the bottomfront, 'bright' part of the image is our side of the orbit and the upper dark area looks like the back of the orbit
8) The variable nature of the light could be scattered matter left behind in the orbital trails or simply timelapse photography. At such an orbital radius, the star's velocity would be very high indeed
9) The scientists presenting this discovery used the terms "I think" and "we think" far too many times to convince us of their interpretation
It is our (here at CalQlata) opinion that the European money would have been better spent discovering for our own galactic forcecentre 'Hades'
Dark Matter
There is no such thing as dark matter.
Notes
 Compared with a radius of 3.26E+12 m for what is claimed to be a supermassive black hole at the centre of Messier 87 (spiral galaxy))
 At radii below (inside) the surface of a star (or planet), gravitational attraction is less than at its surface because there is less mass generating it. Gravitational attraction above (outside) the surface of a star is less than at its surface because its mass does not increase with radius.
 These relationships are representative at the birth of each star and/or stars of similar age, but are approximate for stars of different ages due to the variability of core size and material
 The density of a collapsed star will define its ultimate size, not its gravitational energy. Therefore, whilst the average density of the collapsed star may not be as defined above, any such variation will not affect its ability to trap photons
The average density of iron (7870 kg/m³) for a dead star is estimated based upon this value appearing approximately halfway through its radial distance with lighter elements above this point and denser iron below it.  Schwarzschild formula R = 2.G.m/c² predicts a radius of:
R = 2 x 6.671282E11 x 9.6287854E+37 / 299792458² = 1.42920391736095E+11m  Whilst this calculation is based upon a neutron star comrising compacted neutrons throughout its radial distance, this is highly unlikely. Our Dark Matter? calculations show it to be an iron ball.
Further Reading
You will find further reading on this subject in reference publications^{(55, 60, 61, 62, 63 & 64)}